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September 1, 2014

September 1, 2014

Posted by **angel0** on Saturday, June 30, 2012 at 7:47am.

tan(x/2)=tanx/secx+1

- pre cal -
**Reiny**, Saturday, June 30, 2012 at 8:51amFor this to be true, you must mean

tan(x/2) = tanx/(secx+1)

let Ø = x/2

then we are proving that

tanØ = tan 2Ø/(sec 2Ø + 1)

RS = (sin 2Ø/cos 2Ø)/(1/cos 2Ø + 1)

= (sin 2Ø /cos 2Ø)/( (1 + cos 2Ø)/cos 2Ø

= sin 2Ø/(1 + cos 2Ø)

= 2sinØcosØ/(1 + 2cos^2 Ø - 1)

= sinØ/cosØ

= tanØ or tan (x/2)

= LS

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