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An oil drop is stationary within an electric field of 490 V/m that is set up between two parallel plates. If the volume of the oil drop is 4 X 10 (-19) m3, how many excess electrons does it carry?
(I'll give ya'll just one hint: the fundamental unit of charge e = 1.6 X 10 (-19) C. )

  • physics - ,

    downward force= mg
    upward force= Eq

    so what is the mass? density*volume

    so you need the density of the oil

    q=density*volume*9.8/490 coulombs

    number electrons= q/e

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