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November 26, 2014

November 26, 2014

Posted by **susmita** on Friday, June 29, 2012 at 12:41pm.

- trig -
**Steve**, Friday, June 29, 2012 at 4:31pmtanA = 2 in QIII means

sinA = -2/√5

cosA = -1/√5

cosA/(sin^3A + cos^3A)

= -1/√5 / (-8/5√5 - 1/5√5)

= -1/√5 / (-9/5√5)

= -1/√5 * -5√5/9

= 5/9

that's PI, not PIE!

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