Posted by :) on Friday, June 29, 2012 at 6:19am.
a) s1= vt - for motorist
s2= (1/2)*a*t^2 - for police officer
when the cop cathes up the motorist:
s1 = s2
So vt = (1/2)*a*t^2
15*t= (1/2)*3*t^2
t = 15*2/3 = 10 sec
b) v = u + a*t
= 0 + 3*10 = 30 m/s
c) distance s1=s2= 15*10 = 150m
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