Posted by Anonymous on Thursday, June 28, 2012 at 8:47am.
Usually the first step I take in doing a limit question is to actually substitute the approach value, so I got
lim cos 4x/(1- cos 2x) , as x -->0
--> 1/(1-0)
which is undefined,
so there is not limit, or the result is infinity
check: I tried x = .0001
and got 52631574.74
however, a more careful reading reveals :-)
lim (1-cos4x)/(1-cos2x)
= lim 4sin4x/2sin2x
= lim (4sin2x cos2x)/sin2x
= lim 4cos2x
= 4
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