posted by Joseph on .
A 5.0 kg block of some unknown material is suspended from a spring scale and submerged in water.?
The spring scale reads 39.3 N. What is the specific gravity of the block?
I get 5051.5 kg/m^3 but its incorrect.
Your answer is correct
Weight = gravity – buoyancy force.
W=mg - ρ(w)•V•g,
V=(mg-W)/ ρ(w)•g =(5•9.8-39.3)/1000•9.8=9.9•10^-4 m³.
ρ=m/V=5/9.9•10^-4 =5051.5 kg/m³