Posted by **angela** on Wednesday, June 27, 2012 at 7:30pm.

FIND THE PERIMETER AND AREA OF A RIGHT IF THE SHORTEST SIDE IS 20MM. AND THE LONGEST SIDE IS 52MM. INCLUDE CORRECT UNITS WITH EACH PART OF YOUR SOLUTION.

- geometry -
**Ms. Sue**, Wednesday, June 27, 2012 at 7:32pm
Is this a right TRIANGLE?

If it is, I'll be glad to help you.

- geometry -
**angela**, Wednesday, June 27, 2012 at 7:51pm
YES

- geometry -
**Ms. Sue**, Wednesday, June 27, 2012 at 8:00pm
First, we need to determine the length of the third side by using the Pythagorean Theorem.

a^2 + b^2 = c^2

20^2 + b^2 = 52^2

400 + b^2 = 2704

b^2 = 2304

b = 48

The perimeter is the sum of the three sides.

20 + 48 + 52 = P

The area is found by using this formula:

A = 1/2 * b * h

A = (1/2) * 20 * 48

A = ________sq. mm.

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