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September 1, 2014

September 1, 2014

Posted by **Anonymous** on Wednesday, June 27, 2012 at 1:15pm.

- smallest of 3 integers -
**Steve**, Wednesday, June 27, 2012 at 2:26pm1/(x-1) + 1/x + 1/(x+1) = 47/[(x-1)x(x+1)]

put all over a common denominator of (x-1)x(x+1). The numerators then satisfy

x(x+1) + (x-1)(x+1) + (x-1)x = 47

3x^2 - 1 = 47

3x^2 = 48

x = 4

check:

1/3 + 1/4 + 1/5 = 47/60

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