Tuesday

September 16, 2014

September 16, 2014

Posted by **Anonymous** on Wednesday, June 27, 2012 at 1:15pm.

- smallest of 3 integers -
**Steve**, Wednesday, June 27, 2012 at 2:26pm1/(x-1) + 1/x + 1/(x+1) = 47/[(x-1)x(x+1)]

put all over a common denominator of (x-1)x(x+1). The numerators then satisfy

x(x+1) + (x-1)(x+1) + (x-1)x = 47

3x^2 - 1 = 47

3x^2 = 48

x = 4

check:

1/3 + 1/4 + 1/5 = 47/60

**Answer this Question**

**Related Questions**

math - the sum of the reciprocals of three consecutive positive integers is ...

math - the sum of the reciprocals of 3 consecutive positive integers is 47 ...

math - 1. The largest of five consecutive integers is twice the smallest. Find ...

math - there are three consecutive positive integers such that the sum of the ...

math - A. Four times one odd integer is 14 less than three times the next even ...

Math - The product of three consecutive odd integers reduced by 23 is 99 less ...

math - the sum of the squares of four consecutive positive integers is 734. what...

Math - What is the smallest of 3 consecutive positive integers if the product of...

Math - What is the smallest of 3 consecutive positive integers if the product of...

ALGEBRA. - The product of 2 positive integers is 1000. What is the smallest ...