What is the molar concentration of sodium in a 200ml solution prepared from 1.223g of sodium phosphate?
mols Na3PO4 = grams Na3PO4/molar mass Na3PO4.
mols Na = 3x that.
Then M = mols Na/L soln.
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To calculate the molar concentration (also known as molarity) of sodium in a solution, we need to follow a series of steps. Here's how you can find the molar concentration of sodium in a 200 mL solution prepared from 1.223 g of sodium phosphate:
1. Determine the molar mass of sodium phosphate (Na3PO4):
- The molar mass of sodium (Na) is approximately 22.99 g/mol.
- The molar mass of phosphorus (P) is approximately 30.97 g/mol.
- The molar mass of oxygen (O) is approximately 16.00 g/mol.
- Sodium phosphate (Na3PO4) consists of three sodium atoms (3 * 22.99 g/mol), one phosphorus atom (30.97 g/mol), and four oxygen atoms (4 * 16.00 g/mol).
- Calculate the molar mass of sodium phosphate by adding up these values: (3 * 22.99 g/mol) + 30.97 g/mol + (4 * 16.00 g/mol).
2. Convert the mass of sodium phosphate to moles:
- Divide the given mass of sodium phosphate (1.223 g) by the molar mass of sodium phosphate.
- This gives you the number of moles of sodium phosphate in the solution.
3. Calculate the molar concentration of sodium:
- Since sodium phosphate contains three sodium ions (Na3PO4), the number of moles of sodium is three times the number of moles of sodium phosphate calculated in step 2.
- Divide the number of moles of sodium by the volume of the solution in liters. In this case, the volume is given as 200 mL, which is equal to 0.2 L.
Now that you have the steps, you can calculate the molar concentration of sodium in the solution.