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December 18, 2014

December 18, 2014

Posted by **Jimmy** on Tuesday, June 26, 2012 at 4:30pm.

- Algebra -
**Steve**, Tuesday, June 26, 2012 at 10:46pmif an input pipe could fill the tank in x hours, and the drain could empty it in y hours with no input,

4/x - 1/y = 1/6

3/x - 1/y = 1/10

x=15,y=10

so, if n pipes fill the tank in 3 hours,

n/15 - 1/10 = 1/3

n = 13/2

Hmmm. I was expecting an integer.

- Algebra -
**Jimmy**, Wednesday, June 27, 2012 at 12:58amCould you help explain how T can put the number of pipes over the time to solve this?? I'm afraid I don't understand.

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