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There is a water tank with a drain of an unknown size that is always open. There is a series of input pipes above it which are all the same size. When 4 pipes are on, it takes 6 hours to fill. When 3 pipes are on, it takes 10 hours to fill. How many pipes would it take to fill the tank in 3 hours?

  • Algebra - ,

    if an input pipe could fill the tank in x hours, and the drain could empty it in y hours with no input,

    4/x - 1/y = 1/6
    3/x - 1/y = 1/10


    so, if n pipes fill the tank in 3 hours,

    n/15 - 1/10 = 1/3
    n = 13/2

    Hmmm. I was expecting an integer.

  • Algebra - ,

    Could you help explain how T can put the number of pipes over the time to solve this?? I'm afraid I don't understand.

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