Algebra
posted by Rob on .
I can not get he correct answer 10.
3/3{a+c(b+5)(6+a)}
a=1, b=6, c=4

starting with
3/3{a+c(b+5)(6+a)}
= 3/3{1+(4)((6)+5)(6+1)}
let's work our way from the inside out:
3/3{1+(4)(6+5)(6+1)}
3/3{1+(4)(1)(5)}
3/3{1+4+5)}
3/3{10}
1(10)
10
Note that the division is done first, then the multiplication, lefttoright