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March 29, 2015

Posted by **paukate08** on Tuesday, June 26, 2012 at 7:22am.

- math -
**Reiny**, Tuesday, June 26, 2012 at 8:09amFor a given perimeter, that largest area area of a rectangle is obtained when the rectangle is a square.

so if each side is x ft

x^2 = 80

x = √80 = 4√5

She needs 16√5 ft or appr 35.8 ft of fencing.

With only 12 feet she cannot have a rectangular field of 80 ft

or

with 12 ft of fencing , she can build a 3by3 square which will hold 9 square ft, not the 80 she wants.

Your question is flawed.

- math -- oops -
**Steve**, Tuesday, June 26, 2012 at 11:33amShe has 12

**yards**, or 36 feet of fencing.

That will enclose 9x9 = 81 ft^2, so by moving away from a square, she can use the whole 36 ft to enclose only 80 ft^2.

80 = 16*5 = 4*(4*5) so if the garden is 8x10 feet, its perimeter is 36 and its area is 80

- Thanks Steve - math -
**Reiny**, Tuesday, June 26, 2012 at 12:30pmI violated one of the first rules I taught my students years ago ...

Read the question carefully, and read it more than once.

**Answer this Question**

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