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August 31, 2014

August 31, 2014

Posted by **j** on Tuesday, June 26, 2012 at 4:45am.

A)find the position ,veocity and acceleration at t=2 sec.

B) find the velocity of the particle at origin.

- physics -
**ajayb**, Tuesday, June 26, 2012 at 7:29amA) position: x(2)= (2*2-3)^2= 1m

v = dx/dt = 2(2t-3)*2

so v(2)= 4 m/s

a = dv/dt = 8 m/s^2

B) v at origin: x=0=(2t-3)^2

so t=3/2

at t=3/2, v = 4(2*3/2-3)= 0

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