Wednesday
March 29, 2017

Post a New Question

Posted by on .

2 queations:
1) a proton enters a magnetic feild at a right angle to the field. an alpja particle enters the same field at the same angle but with twice the speed. once in the magnetic field both particles move in a circular path. the raito of radius of the alpha particles path to the radius of the protons path is?
[4:1]

2) a proton and an alpha particle have an identical circular orbits in a magnetic field. the proton has a speed of 4.4 m/s. the speed of the aplha particle is?
[2.2^5 m/s]

thank you

  • Physics - ,

    1) r = m*v/(q*B)
    r(a)= m(a)*2v/(q(a)*B).....(1)
    r(p)= m(p)*v/(q(p)*B).....(2)

    r(a)/r(p)= m(a)*2v*q(p)/[m(p)*v*q(a)]
    = 4m(p)*2*q(p)/[m(p)*2q(p)]
    = 4*2/2 = 4

    2) Ma*Va/[Qa*B] = Mp*Vp/[Qp*B]
    So, Va = 4.4*2/4 = 2.2m/s

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question