Thursday

April 2, 2015

April 2, 2015

Posted by **gagaformath** on Monday, June 25, 2012 at 7:51pm.

this was the original: (t^2-1?t^2+1)^3

and then I got the derivative which looked like this after I finished all the other steps:

3(t^2-1/t^2+1)^2d(t^2+1)(2t)-(t^2-1)(2t)/ (t^2+1)^2

So now, the answer is 3(t^2-1/t^2+1)^2d 4t/(t^2+1)^2

But I am not sure how to from the part I did to the answer...can someone please explain?

- calculus -
**Steve**, Tuesday, June 26, 2012 at 12:03amwhew - try some proofreading. It appears you want the derivative of

((t^2-1)/(t^2+1))^3

and you applied the chain rule to get

3(t^2-1/t^2+1)^2 * ((t^2+1)(2t))-(t^2-1)(2t))/(t^2+1)^2

So far so good, with the calculus. Now start using that half-forgotten algebra:

(t^2+1)(2t))-(t^2-1)(2t) = 2t^3 + 2t - 2t^3 + 2t = 4t

and go directly from there to the given answer (where "d" apparently means *)

**Answer this Question**

**Related Questions**

calculus - f(x) = 6x^2 -8x +3 how would I find the most general antiderivative ...

Calculus (Help) - Also I would like to know how to set this problem up in ...

College Calculus 1 - We have to find the first and second derivative of f(x)=x^(...

Math Calculus - Let C(x) = 0.02x^3 + 55x^2 + 1380. Find the minimum average cost...

Algebra - The answer in the book however says -(5x^2-17x-9)/(x-3)(x+2) so I don'...

Calculus - I finished this problem but I wanted some feedback because I don't ...

Calculus - We are doing problems with the product and quotient rules, but I'm ...

Calculus - relative extrema x^4-2x^2+5 so far I know how to find the derivative ...

calculus - So from a previous post I asked, "f(x)=(1+x) what is f'(x) when x=0...

Calculus again - Find the equation of the tangent to y=2-xe^x at the point where...