I don't know if i did this correct.
c+(4-3c)-2=0
c+1c-2=0
1c-2=0
-1=0
c= -1 ?
Nope
C+4-3c-2= now collect terms
-2c+2=0 then add 2c to each side
2=2c now divide both sides by 2
c=1
3a+2b+1c,3a+2b+1c by changing multiply
To solve the equation c + (4 - 3c) - 2 = 0, let's go through the steps together:
1. Start by simplifying the expression inside the parentheses: 4 - 3c. This becomes 4 - 3c.
2. Now, replace the original equation with the simplified expression: c + (4 - 3c) - 2 = 0 becomes c + (4 - 3c) - 2 = 0.
3. Next, distribute the positive sign to the terms inside the parentheses: c + 4 - 3c - 2 = 0.
4. Combine like terms: (c - 3c) + (4 - 2) = 0 => -2c + 2 = 0.
5. Simplify further: -2c + 2 = 0. Subtract 2 from both sides: -2c = -2.
6. Divide both sides by -2 to solve for c: (-2c)/-2 = (-2)/-2 => c = 1.
Therefore, the correct solution for c is c = 1. It seems there was an error in your calculations. Please double-check your work and follow the steps provided above to solve this equation.