Peter is reading a 193-book. He has three pages more than one fourth of the number of pages he hasn't read.

a. How many pages has he not read?
b. Estimate how many days it will take Peter to finish the book if reads about 8 pages per day.

3+N/4=193-N N=pages not read

I assume you meant to write he has read three more ....

To solve this problem, we'll use algebra to find the number of pages Peter hasn't read yet.

Let's assume the number of pages Peter has not read yet is x.
According to the problem, Peter has three pages more than one fourth of the number of pages he hasn't read. Mathematically, this can be represented as:

x/4 + 3 = x

Now, let's solve for x.

Subtracting x/4 from both sides of the equation, we have:
3 = x - x/4

To simplify, we'll express both terms over the same denominator:
3 = (4x - x)/4

Combining like terms:
3 = 3x/4

To isolate x, we'll multiply both sides of the equation by 4/3:
3 * 4/3 = x
4 = x

a. Therefore, Peter has not read 4 pages.

Now, let's estimate how many days it will take Peter to finish the book if he reads about 8 pages per day.

If Peter reads about 8 pages per day, and the total number of pages is 193, we can find the number of days needed by dividing the total number of pages by the number of pages he reads per day:

193 / 8 = approximately 24.125

Since we can't have a fraction of a day, we'll round up to the nearest whole number. Therefore, it will take Peter approximately 25 days to finish the book.