x1= 0.8m -the distance between supports.
x2= 1.2 m - the distance between the right-hand support anf the center of mass of the board,
x3 =3.2 m the distance between the right-hand support and the diver.
m1= 50 kg, m1g = 490 N,
m2= 60 kg, m2g = 588 N.
F1 is the downward force on the left-hand support,
F2 is the upward force on the right-hand support.
Three torques act about the right support
τ2 = - m1gx2,
τ3 = - m2gx3,
Σ τ= τ1 +τ2 +τ3 = 0,
F10.8 - 4901.2 - 5883.2 = 0,
F1=(4901.2 + 5883.2)/0.8 =3087 N
ΣF = - F1 + F2 - m1g - m2g = 0,
F2 = 3087+ 490+588=4165 N