An oceanic depth-sounding vessel surveys the ocean bottom with ultrasound waves

that travel at 1530 m/s in seawater. The time delay of an echo to the ocean floor
below is 3 seconds. Find the depth of the water.

The sound traveled twice the depth of the water (down and back).

2*depth=1530m/s*3seconds

From,

Speed=distance/time
Where,
S=1,530m/s, t=3s and d=?
=> d=s*t
D=1,530*3
D=4,590m

In order to find the depth of the water, we can use the formula:

Depth = (Speed of Sound × Time Delay) / 2

Given that the speed of sound in seawater is 1530 m/s and the time delay is 3 seconds, we can substitute these values into the formula:

Depth = (1530 m/s × 3 s) / 2

Simplifying the equation:

Depth = (4590 m) / 2

Dividing 4590 by 2 gives us:

Depth = 2295 m

Therefore, the depth of the water is 2295 meters.