Posted by Jeff on Sunday, June 24, 2012 at 9:02am.
I do not know where to start with this one. Suppose p varies directly as the square of z and inversely as r. If p = 32/5 when z = 4 and r = 10, find p when z = 3 and r = 36.

algebra  Reiny, Sunday, June 24, 2012 at 10:13am
" p varies directly as the square of z and inversely as r "
> p = k (√z) (1/r) , where k is a constant
given: p=32/5 , z=4, r=10
32/5 = k(√4)(1/10)
times 10
64 = 2k
k = 32
so p = 32√z/r
then when z=3,r=36
p = 32√3/36
= 8√3/9 or appr 1.54

algebra  christina, Sunday, June 24, 2012 at 5:46pm
6x+4(70x)=300
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