Posted by **Jeff** on Sunday, June 24, 2012 at 9:02am.

I do not know where to start with this one. Suppose p varies directly as the square of z and inversely as r. If p = 32/5 when z = 4 and r = 10, find p when z = 3 and r = 36.

- algebra -
**Reiny**, Sunday, June 24, 2012 at 10:13am
" p varies directly as the square of z and inversely as r "

----> p = k (√z) (1/r) , where k is a constant

given: p=32/5 , z=4, r=10

32/5 = k(√4)(1/10)

times 10

64 = 2k

k = 32

so p = 32√z/r

then when z=3,r=36

p = 32√3/36

= 8√3/9 or appr 1.54

- algebra -
**christina**, Sunday, June 24, 2012 at 5:46pm
6x+4(70-x)=300

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