Posted by jo on Saturday, June 23, 2012 at 10:30pm.
Assume:
1. no air resistance
2. initial speed (Vi) = "average speed" = 6000 mph
Change in vertical altitude after time t
=Vi*sin(θ)t - (1/2)gt²
Vi = initial velocity = 6000 mph = 8800 ft/s
t=time since launch = 120 s.
θ=launch angle above horizontal = 26.5°
g=acceleration due to gravity = 32.2 ft/s²
Work with feet and seconds.
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