posted by Maria on .
What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V?
Given: A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25degrees C . The initial concentrations of Pb2+ and Cu2+ are 5.30×10−2 M and 1.60 M, respectively.
The Einitial cell that I calculated was 0.47. I know how to figure out the Q, but I don't know how to figure out the specific concentrations of Pb2+ and Cu2+ given only this information. Please help me! Thank you :)