Saturday

August 23, 2014

August 23, 2014

Posted by **Liza** on Saturday, June 23, 2012 at 9:41am.

--------------------------------------

Solution: We need to find the connection between the height and time. With “down” positive, so a=g is positive, and with v0 = 0, distance = (1/2) at^2 ? h = (1/2)gt^2 ? h = t^2. Therefore, if we double t, h must increase by a factor of 2^2 = 4.

--------------------------------------

My Question: I don't understand how they are able to just equate h with t^2 (h=t^2). Then say that the answer is 4h. I thought the answer would be 2gh. But then why is it that gravity isn't included in the final answer?

THANKS!

- Physics -
**bobpursley**, Saturday, June 23, 2012 at 10:41amIt is in the final answer, but it has divided out.

h(t)=1/2 g t^2

newheight=1/2 g(2t)^2=1/2 4t^2

so to find newheight, divide the second equation by the first.

hewheight/oldheight=4

newheight=4*oldheight

**Related Questions**

physics - n object is dropped from rest from a height 5.8 × 106 m above the ...

Physics - a. 2 objects each of mass 200 kg and 500 kg are separated by 50 cm. ...

Algebra - The gravitational force between an object & the Earth is inversely ...

University Physics (Cal-Based) - Calculate the velocity of a 20kg object that is...

earth - A particle weighs 120 N on the surface of the earth. At what height ...

physics - when an object is 100m above the surface of earth. The earth's ...

phys - An astronaut drops an object from rest (relative to the planet) on a ...

MATH - Can someone please help me with the following question. 1) The weight of...

Pre-Calc H.W. Help :) - Can someone please help me with the following question...

Pre-Calculus - Can someone please help me with the following question. 1) The ...