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July 25, 2014

July 25, 2014

Posted by **noel** on Friday, June 22, 2012 at 5:06pm.

1. tanx = sinx + sin^2x/cosx(1+sinx)

2. cos^3+(cosx)(sin^2x) = 1/secx

- trigonometric identities -
**Reiny**, Friday, June 22, 2012 at 5:14pm1. The way you typed it, the identity is false, but I am sure you meant

tanx = (sinx + sin^2x)/(cosx(1 + sinx))

RS = sinx(1 + sinx) / (cosx(1+sinx))

= sinx/cosx

= tanx

= LS

2. LS = cosx(cos^2x + sin^2x)

= (cosx)(1)

= cosx

RS = 1/secx

= cosx

= LS

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