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December 20, 2014

December 20, 2014

Posted by **Dipankar** on Friday, June 22, 2012 at 5:04pm.

- Math -
**Reiny**, Friday, June 22, 2012 at 5:19pmif 1 - cosA = 5/13

then cosA = 1-5/13 = 12/13

A could be in I or IV

For I:

cosA = 12/13

then sinA = 5/13

25sinA(sinA-cosA_ = 25(5/13)(5/13 - 12/13)

= ...

for IV

cosA = 12/13

then sinA = -5/13

25sinA(sinA - cosA)

= 25(-5/13)(-5/13 - 12/13)

= ....

I will leave the arithmetic up to you

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