Posted by Dipankar on Friday, June 22, 2012 at 5:04pm.
if 1 - cosA = 5/13
then cosA = 1-5/13 = 12/13
A could be in I or IV
For I:
cosA = 12/13
then sinA = 5/13
25sinA(sinA-cosA_ = 25(5/13)(5/13 - 12/13)
= ...
for IV
cosA = 12/13
then sinA = -5/13
25sinA(sinA - cosA)
= 25(-5/13)(-5/13 - 12/13)
= ....
I will leave the arithmetic up to you
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