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November 27, 2014

November 27, 2014

Posted by **Sarah** on Friday, June 22, 2012 at 11:05am.

- Physics -
**ajayb**, Saturday, June 23, 2012 at 4:22pmS=(1/2)gt^2 since u=0

4000=(1/2)*10*t^2

t=sqrt(800)secs - time to reach ground

So hor. distance covered= 80*sqrt(800)

= 2263m

- Physics -
**Henry**, Saturday, June 23, 2012 at 4:39pmh = ho - o.5g*t^2 = 0

4000 - 4.9t^2 = 0

-4.9t^2 = -4000

t^2 = 816.3

Tf = 28.6 s. = Fall time or time in flight.

Dx = Hor = 80m/s * 28.6s = 2286 m.

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