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College algebra

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A cyclist bikes at a constant speed for 18 miles. He then returns home at the same speed, but takes a different route. His return trip takes one hour longer and is 23 miles. Find his speed

  • College algebra -

    let the speed be x mph

    time for first trip = 18/x
    time for 2nd trip = 23/x

    23/x - 18/x = 1
    5/x = 1
    x = 5

    his speed is 5 mph

    time for 1st trip = 18/5 = 3.6 hrs
    time for 2nd trip = 23/5 = 4.6 hrs, which is 1 hour more

  • College algebra -

    Let X be distance per hour,
    Ist trip=18miles =18/X
    2nd trip=23miles =23/X,=1hr longer
    speed,S=2nd trip-1st trip

    23/5 -18/5 =4.6-3.6=1hr

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