Posted by **Anonymous** on Friday, June 22, 2012 at 10:54am.

A cyclist bikes at a constant speed for 18 miles. He then returns home at the same speed, but takes a different route. His return trip takes one hour longer and is 23 miles. Find his speed

- College algebra -
**Reiny**, Friday, June 22, 2012 at 11:10am
let the speed be x mph

time for first trip = 18/x

time for 2nd trip = 23/x

23/x - 18/x = 1

5/x = 1

x = 5

his speed is 5 mph

check:

time for 1st trip = 18/5 = 3.6 hrs

time for 2nd trip = 23/5 = 4.6 hrs, which is 1 hour more

- College algebra -
**Blessing**, Friday, June 22, 2012 at 8:51pm
Let X be distance per hour,

Ist trip=18miles =18/X

2nd trip=23miles =23/X,=1hr longer

speed,S=2nd trip-1st trip

X=23-18

X=5mph.

checkings

23/5 -18/5 =4.6-3.6=1hr

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