Alamo, Brushy, Chet, and Dolly are in an armadillo race. Chet is the
slowest. Dolly is faster than Alamo, but slower than Brushy. Name the
finishing order of the armadillos.
X=individual yet unknown
Left-most is the fastest
A,B,C,D=the four individuals.
"Chet is the slowest" => XXXC
"Dolly is faster than Alamo, but slower than Brushy"
=>
XXX=BDA
So can you take it from here?
D=chet(the slowest)
C=Alamo
B =Dolly
A=Brushy
Correct! Good job!
By the way, are you chchch or Blessing?
To determine the finishing order of the armadillos, we need to analyze the given information. Let's break it down step by step:
1. Chet is the slowest.
This tells us that Chet is in the last position.
2. Dolly is faster than Alamo.
From this, we can conclude that Dolly is not in the last position, and Alamo must be behind Dolly.
3. Dolly is slower than Brushy.
This statement implies that Brushy is ahead of Dolly.
Now, let's put all the information together to determine the finishing order:
1. Brushy
2. Dolly
3. Alamo
4. Chet
So, Brushy finishes in the first position, followed by Dolly, then Alamo, and finally Chet in the last position.