A gas, while expanding under isobaric conditions, does 660 J of work. The pressure of the gas is 1.40 x 105 Pa, and its initial volume is 1.70 x 10-3 m3. What is the final volume of the gas?
Would I multiply the two values?
W = p*dV = p(Vf - Vi)--for isbaric p is constant.
Plug in values of W,p and Vi to find Vf
To find the final volume of the gas, you cannot simply multiply the pressure and initial volume. Instead, you need to use the formula for work done by a gas under isobaric conditions.
The formula for work done by a gas under isobaric conditions is given by: Work = Pressure * Change in Volume
Let's denote the final volume of the gas as Vf and the initial volume as Vi. The change in volume is then given by: ΔV = Vf - Vi
In this case, you know the initial volume (Vi = 1.70 x 10^-3 m^3) and the work done by the gas (Work = 660 J), as well as the pressure (1.40 x 10^5 Pa). We can rearrange the formula as:
Work = Pressure * ΔV
Solving for ΔV:
ΔV = Work / Pressure
Now you can substitute the given values into the formula and calculate the change in volume:
ΔV = 660 J / (1.40 x 10^5 Pa)
Calculating the ΔV gives you the change in volume. To find the final volume (Vf), you need to add the change in volume to the initial volume:
Vf = Vi + ΔV
Substitute the initial volume (Vi) and the calculated ΔV into the equation and solve for Vf to find the final volume of the gas.