Homework Help: Physics(Please check)

Posted by Hannah on Thursday, June 21, 2012 at 7:05pm.

A paperweight, when weighed in air, has a weight of W = 6.95 N. When completely immersed in water, however, it has a weight of Win water = 4.26 N. Find the volume of the paperweight.

Would I multiply the two values of weight and then by the density of water?

4.26=weightinair-forcebouyancy
4.26=6.95-desnisitywater*g*volume

solve for volume

So would I set it up as
4.26= 6.95 - 1000(9.8)V ?

Physics(Please check) - Damon, Thursday, June 21, 2012 at 7:56pm
weight of water displaced = 6.95 - 4.26 = 2.69 N
2.69 N = Vol * 1000Kg/m^3 * 9.81 m/s^2
so
Yes

Answer this Question

Related Questions

Physics(Please help) - A paperweight, when weighed in air, has a weight of W = 6...
physics - A paperweight, when weighed in air, has a weight of W = 6.8 N. When ...
Physics - A paperweight, when weighed in air, has a weight of W = 7.5 N. When ...
Physics - A cell phone, when weighed in air has a weight of 5.5 newton. When ...
physics - A paperweight weighs 6.9N in air. When it is completely submerged in ...
physics - A paperweight weighs 6.9N in air. When it is completely submerged in ...
physics - A paperweight weighs 6.9N in air. When it is completely submerged in ...
Physics - An object weighing 400.0g in air is immersed in water after being tied...
Science- physics - An iron anchor weighs 250 pounds in air and has a weight ...
Physics - A solid of density 5000 kg/m^3 weighs 0.5 kgf in air.It is completely ...

For Further Reading

First Name:
School Subject:
Answer: