Posted by Hannah on Thursday, June 21, 2012 at 7:05pm.
A paperweight, when weighed in air, has a weight of W = 6.95 N. When completely immersed in water, however, it has a weight of Win water = 4.26 N. Find the volume of the paperweight.
Would I multiply the two values of weight and then by the density of water?
4.26=weightinairforcebouyancy
4.26=6.95desnisitywater*g*volume
solve for volume
So would I set it up as
4.26= 6.95  1000(9.8)V ?

Physics(Please check)  Damon, Thursday, June 21, 2012 at 7:56pm
weight of water displaced = 6.95  4.26 = 2.69 N
2.69 N = Vol * 1000Kg/m^3 * 9.81 m/s^2
so
Yes