A paperweight, when weighed in air, has a weight of W = 6.95 N. When completely immersed in water, however, it has a weight of Win water = 4.26 N. Find the volume of the paperweight.
Would I multiply the two values of weight and then by the density of water?
solve for volume
So would I set it up as
4.26= 6.95 - 1000(9.8)V ?
Physics(Please check) - Damon, Thursday, June 21, 2012 at 7:56pm
weight of water displaced = 6.95 - 4.26 = 2.69 N
2.69 N = Vol * 1000Kg/m^3 * 9.81 m/s^2