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December 18, 2014

December 18, 2014

Posted by **Amarjeet** on Thursday, June 21, 2012 at 2:40pm.

- calculuss review for exam -
**Steve**, Thursday, June 21, 2012 at 3:35pmsince y'' = 2 any max/min will be a min.

- calculuss review for exam -
**Amarjeet**, Thursday, June 21, 2012 at 3:42pmwhat do you mean by that? :/

- calculuss review for exam -
**Steve**, Thursday, June 21, 2012 at 3:50pmTake a look at the explanation of the 2nd derivative test. If y'' < 0 you have a max, and if y'' > 0 you have a min where y'=0.

- calculuss review for exam -
**Amarjeet**, Thursday, June 21, 2012 at 3:54pmif y' = 0 doesn't that mean there is no max or min? im sorry but i really don't understand this.. please help me

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