Posted by **Lilliana** on Thursday, June 21, 2012 at 2:38pm.

use the first derivate test to locate the maxima and minima of y = x^(1/3)

- Calculus review -
**Steve**, Thursday, June 21, 2012 at 3:37pm
since y' = 1/3 * 1/x^(2/3) is never zero, there is no max/min.

Think of the graph. Cube root just gets bigger and bigger, the farther away from zero.

- Calculus review -
**Lilliana**, Thursday, June 21, 2012 at 3:44pm
THANKS STEVE, YOU'RE THE BEST!

## Answer This Question

## Related Questions

- calculuss review for exam - use the second derivate test to locate the maxima ...
- basic calculus - use the first and second derivatives to find the x-coordinates ...
- college algebra - Let f(x)= x^5/120 - x^3/6 + x Find the local minima and maxima...
- Maxima and minima Application - Find the maxima and minima coordinates of the ...
- math about to have a test over this please help! - Unfortunately that is the ...
- Minima Maxima - Find and classify the relative maxima and minima of f(x) if f(x...
- physics - A monochromatic light illuminates a double slits system with a slit ...
- Derivative Test - Consider the function y = 3x5 – 25x3 + 60x + 1. Use the first ...
- Calculus - True or False: Consider the following statement: A differentiable ...
- Calculus (pleas help!!!) - Let p(x)=x^2(a−x), where a is constant and a ...

More Related Questions