Posted by Albert on Thursday, June 21, 2012 at 2:15pm.
4y^3 y' = 6x-2
y' = (6x-2)/(4y^3)
at (1,1) y' = 4/4 = 1
line is thus (y-1) = 1(x-1)
y = x
thank you for taking your time to answer my questions steve!
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