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March 29, 2017

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hi i need help differentiating these..

1. y = cos(3x^2 + 2x)

2. y = ln(3x^2 + 5)

thank you

  • Calculus grade 12 - ,

    use the old chain rule:

    y = cos(u)
    y' = -sin(u) u' = -sin(3x^2+2x)(6x+2)

    y = ln(u)
    y' = 1/u u' = 1/(3x^2+5) * 6x = 6x/(3x^2+5)

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