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October 1, 2014

October 1, 2014

Posted by **Albert** on Thursday, June 21, 2012 at 1:46pm.

1. y = cos(3x^2 + 2x)

2. y = ln(3x^2 + 5)

thank you

- Calculus grade 12 -
**Steve**, Thursday, June 21, 2012 at 3:54pmuse the old chain rule:

y = cos(u)

y' = -sin(u) u' = -sin(3x^2+2x)(6x+2)

y = ln(u)

y' = 1/u u' = 1/(3x^2+5) * 6x = 6x/(3x^2+5)

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