Monday

March 30, 2015

March 30, 2015

Posted by **Albert** on Thursday, June 21, 2012 at 1:46pm.

1. y = cos(3x^2 + 2x)

2. y = ln(3x^2 + 5)

thank you

- Calculus grade 12 -
**Steve**, Thursday, June 21, 2012 at 3:54pmuse the old chain rule:

y = cos(u)

y' = -sin(u) u' = -sin(3x^2+2x)(6x+2)

y = ln(u)

y' = 1/u u' = 1/(3x^2+5) * 6x = 6x/(3x^2+5)

**Answer this Question**

**Related Questions**

Calculus II - How does one obtain cos2x = cos^2(x) - sin^2(x) by differentiating...

calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...

Grade 12 Calculus - I need helping in filling in the blanks/ -the angle formed...

Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...

Calculus - Integrate x dx/(1-x). I have proceeded thus- Int xdx/(1-x)=int -(x-1+...

Calculus I - cos(2x)−cos(x) = -((sin^2)x + 1/4) Need help solving.

Math - Calculus - The identity below is significant because it relates 3 ...

Calculus - which of the following integrals results from making the substitution...

Calculus - 6x-3y=4 find dy/dx using differentiating implicity

Calculus - what is the limit n to infinite of cos1*cos(1/2)*cos(1/4)*cos(1/8)*...