Determine the coefficient of x^5 in the binomial expansion of (2-3x)^7?

(2-3x)^7

= 2^7 + C(7,1)(2^6)(-3x) + C(7,2)(2^5)(-3x)^2 +...+ C(7,5)(2^2)(-3x)^5 + ...

so we want C(7,5)(2^2)(-3x)^5

= 21(4)(-243)x^5
= - 20412x^5

check my arithmetic