i am a four digit numeral number between 3000 and 4000.My ones digit is 3 greater than my thousands digit.The two other digits are the same.If the sum of my digit is 20,what number am i?
So the number must look like
3xxx
"My ones digit is 3 greater than my thousands digit"
so it must be 3xx6
"The two other digits are the same" ---> 3AA6
"the sum of my digits is 20"
---> 3+A+A+6=20
2A= 11
A is not a whole number, so your question is bogus!
Oh, sorry. It was 2, not 3 ..
So make the necessary changes in my solution, I am sure you can do it.
I just did.. Thanks! Was it 3665?
To find the four-digit number described in the question, we can begin by breaking down the information given into smaller steps:
Step 1: Identify the range of the four-digit number.
The number is between 3000 and 4000.
Step 2: Determine the relationship between the ones digit and the thousands digit.
The ones digit is 3 greater than the thousands digit.
Step 3: Identify the repeating digit.
The two other digits are the same.
Step 4: Determine the sum of all the digits.
The sum of all the digits is 20.
Now, let's find the four-digit number.
Step 1: Since the number is between 3000 and 4000, it must be in the form of 3XXX.
Step 2: The ones digit is 3 greater than the thousands digit. Therefore, we have three options for the value of the thousands digit (X):
- If the thousands digit (X) is 1, then the ones digit is 4.
- If the thousands digit (X) is 2, then the ones digit is 5.
- If the thousands digit (X) is 3, then the ones digit is 6.
Step 3: The two other digits are the same, so we have one more digit (Y). Since the sum of all digits is 20, we can form an equation:
Thousands digit (X) + Thousands digit (X) + Ones digit (6) + Same digit (Y) = 20
Simplifying the equation, we get: 2X + 6 + Y = 20 or 2X + Y = 14.
Step 4: Considering the equation 2X + Y = 14, we can check the values of X and Y to satisfy the equation and find the repeating digit:
- If X = 1 and Y = 2, the equation becomes 2(1) + 2 = 4, which is not equal to 14.
- If X = 2 and Y = 4, the equation becomes 2(2) + 4 = 8, which is not equal to 14.
- If X = 3 and Y = 8, the equation becomes 2(3) + 8 = 14, which is equal to 14.
Therefore, the thousands digit (X) is 3, the ones digit is 6, and the repeating digit (Y) is 8.
Thus, the four-digit number that satisfies all the given conditions is 3,868.