Calculus 1
posted by
Max on
.
Derivative of 7^(SinX)... something to do with log/ln?

Calculus 1 
Janelle,
You have to use the chain rule.
ln(7) * 7^(sin x) * cos (x)

Calculus 1 
Reiny,
let y = 7^(sinx)
take ln of both sides
ln y = ln (7^sinx)
ln y = sinx (ln7)
now use the rule for ln
y' /y = ln7(cosx)
y' = ln7(cosx) * (7^sinx)