Posted by **Max** on Thursday, June 21, 2012 at 2:18am.

Derivative of 7^(SinX)... something to do with log/ln?

- Calculus 1 -
**Janelle**, Thursday, June 21, 2012 at 2:24am
You have to use the chain rule.

ln(7) * 7^(sin x) * cos (x)

- Calculus 1 -
**Reiny**, Thursday, June 21, 2012 at 7:49am
let y = 7^(sinx)

take ln of both sides

ln y = ln (7^sinx)

ln y = sinx (ln7)

now use the rule for ln

y' /y = ln7(cosx)

y' = ln7(cosx) * (7^sinx)

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