Thursday

July 31, 2014

July 31, 2014

Posted by **steven** on Wednesday, June 20, 2012 at 8:16pm.

- algebra -
**MathMate**, Wednesday, June 20, 2012 at 8:41pmBy system of equations:

C=number of child tickets sold

A=number of adult tickets sold

C+A = 25

6C+16A = 260

Solve for A and C (by substitution).

Solving the problem in the head without pencils or paper or calculator:

Adult tickets cost $10 more than child tickets. If all 25 were child tickets, they would have gathered 6*25=$150.

To get $260, there must have been (260-150)/10=11 adults.

So there were 11 adults and 14 children.

**Related Questions**

algebra - Adult tickets for a play cost $16 and child tickets cost $5. If there ...

algebra - Adult tickets for a play cost $13 and child tickets cost $3. If there ...

math - Adult tickets for a play cost $13 and child tickets cost $10. If there ...

math - Adult tickets for a play cost $19 and child tickets cost $17. If there ...

math - Adult tickets for a play cost $19 and child tickets cost $10. If there ...

Math - Adult tickets for a play cost $19 and child tickets cost $17. If there ...

math - Adult tickets for a play cost $19 and child tickets cost $17. If there ...

Math - Adult tickets for a play cost $15 and child tickets cost $6. If there ...

math - Adult tickets for a play cost $15 and child tickets cost $6. If there ...

Algebra - Adult tickets for a play cost $9 and child tickets cost $8. If there ...