Posted by steven on Wednesday, June 20, 2012 at 8:16pm.
By system of equations:
C=number of child tickets sold
A=number of adult tickets sold
C+A = 25
6C+16A = 260
Solve for A and C (by substitution).
Solving the problem in the head without pencils or paper or calculator:
Adult tickets cost $10 more than child tickets. If all 25 were child tickets, they would have gathered 6*25=$150.
To get $260, there must have been (260-150)/10=11 adults.
So there were 11 adults and 14 children.
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