Posted by dylan on Wednesday, June 20, 2012 at 6:41pm.
let the number of 10 cent decreases by n
then price of fries = 2.75-.1n
number sold = 425 + 20n
revenue = (2.75-.1n)(425+20n)
d(revenue)/dx = (2.75-.1)(20) + (425+20n)(-.1) = 0 for a max of revenue
55 - 2n - 42.5 - 2n = 0
-4n = -12.5
n = 3.125
I would assume that the decreases would be complete multiples of 10 cents, so there should be 3 decreases or a 30 cent decrease
when n = 3
they will have a price of 2.45
and they will sell 485
revenue = 2.45(485) = 1188.25
check:
if n=2
revenue = 2.55(465) = 1185.75 , which is lower
if n=4
revenue = 2.35(505 = 1186.75 , which is also lower than the n=3 value
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