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November 29, 2014

November 29, 2014

Posted by **Anonymous** on Wednesday, June 20, 2012 at 3:56pm.

x^3+9x^2+33x+15 slope= 6

- calculus -
**Reiny**, Wednesday, June 20, 2012 at 6:45pmYou should have properly written the function as

y = x^3 + 9x^2 + 33x + 15

or

f(x) = x^3 + 9x^2 + 33x + 15

then dy/dx = 3x^2 + 18x + 33

but you want that to be 6

3x^2 + 18x + 33 = 6

x^2 + 6x + 9 = 0

(x+3)^2 = 0

x+3 = 0

x = -3

then f(3) = -27 + 81 - 99 + 15 = -30

The point is (-3,-30)

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