Posted by Caitlyn on Wednesday, June 20, 2012 at 11:52am.
We don't have your diagram, so we don't know how the masses are connected.
Please describe your figure.
Oh sorry I completely forgot to add that part in. It's a right triangle and mass A is on the incline (hypotenuse) portion and is attached to a pulley and on the other end is mass B hanging down the side that would be the height of the triangle (opposite of the angle). Is that clear enough?
The tension in the string will be equal to T, which connects both masses A and B.
For mass A, the force down the incline is Ma*g*sin(θ) which equals T.
For mass B, the force due to gravity is Mb*g which also equals T.
Thus, equating the two values of T, we get:
Ma*g*sin(θ)=Mb*g
sin(θ)=Mb*g/(Ma*g)
=Mb/Ma
=0.125/0.5
=1/4
Can you take it from here?
Yea I got it! Thanks a lot!
You're welcome!
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