Posted by Bland on Tuesday, June 19, 2012 at 11:43pm.
A ball is thrown directly upward with an initial velocity of 12 m/s. If the ball is released from an initial height of 2.9 m above ground, how long is the ball in the air before landing on the ground? Ignore air drag.

Physics  drwls, Wednesday, June 20, 2012 at 1:54am
height above ground =
Y = 12 t  4.9 t^2 + 2.9
SWet that eq

Physics  drwls, Wednesday, June 20, 2012 at 2:02am
height above ground =
Y = 12 t 4.9 t^2 + 2.9 (meters)
Set Y equal to zero and solve for t.
4.9t^2 12t 2.9 = 0
There will be two solutions. Take the positive one.
Use thye "quadratic formula":
t = (1/9.8)[12 + sqrt(144 + 56.84)]
= 2.671 s
Answer This Question
Related Questions
 Physics  A ball is thrown directly upward with an initial velocity of 14 m/s. ...
 Physics  A red ball is thrown down with an initial speed of 1.3 m/s from a ...
 physics  A red ball is thrown down with an initial speed of 1.2 m/s from a ...
 algebra 2  A ball is thrown directly upward from an initial height of 200 feet ...
 Physics  A blue ball is thrown upward with an initial speed of 19.6 m/s, from a...
 Physics  A tennis player hits a ball at ground level, giving it an initial ...
 Physics  A tennis player hits a ball at ground level, giving it an initial ...
 physics  A ball rolls along a desktop with an uniform velocity of 3 m/s. What ...
 physics  A ball rolls along a desktop with an uniform velocity of 3 m/s. What ...
 college  A blue ball is thrown upward with an initial speed of 19.8 m/s, from ...
More Related Questions