Posted by Joey on Tuesday, June 19, 2012 at 8:57pm.
Let the starting point be in the origin of coordinate system. Then the points of the hicker’s route are A , B and C.
AB=10 => A (7.1; 7.1),
BC =5 => B(2.1; 7.1),
BC=2 => C (2.1; 5.1)
Displacement BC = sqrt(2.1²+5.1²)=5.22 km
The angle with +x-axis is arctan(5.1/2.1)=67.6º
s=10+5+2=17 km,
v=s/t=17/2.5 =6.8 km/h
L=10+5+2+5.22 =22.22 km,
t1=L/v=/6.8=3.27 h.
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