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April 25, 2014

April 25, 2014

Posted by **Joey** on Tuesday, June 19, 2012 at 8:57pm.

(a) What is the hiker's displacement?

(b) In what direction must the hiker set out, in order to return by the most direct route to the starting point?

(c) If the hiker walks at a constant speed for the entire trip and returns by the most direct route, how long will the total walk take?

Thanks!

- Physics: Vectors -
**Elena**, Wednesday, June 20, 2012 at 2:11amLet the starting point be in the origin of coordinate system. Then the points of the hicker’s route are A , B and C.

AB=10 => A (7.1; 7.1),

BC =5 => B(2.1; 7.1),

BC=2 => C (2.1; 5.1)

Displacement BC = sqrt(2.1²+5.1²)=5.22 km

The angle with +x-axis is arctan(5.1/2.1)=67.6º

s=10+5+2=17 km,

v=s/t=17/2.5 =6.8 km/h

L=10+5+2+5.22 =22.22 km,

t1=L/v=/6.8=3.27 h.

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