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December 20, 2014

December 20, 2014

Posted by **Hollie** on Tuesday, June 19, 2012 at 7:31pm.

I can't seem to figure out the answer to this problem.

Thanks to anyone who can help!

*Solve the system of equations. Write your solution(s) in the form (x,y).

y = x^2

x^2 + y^2 = 20

- Math -
**bobpursley**, Tuesday, June 19, 2012 at 7:53pmx^2+x^4-20=0

(x^2-4)(x^2+5)=0

(x+2)(x-2)(x^2+5)=0

x= +-2, x= +-sqrt(-5

(2,4)(-2,4)(sqrt-5,-5)(-sqrt-5, -5)

- Math -
**Damon**, Tuesday, June 19, 2012 at 7:54pmy + y^2 = 20

y^2 + y - 20 = 0

(y-4)(y+5) = 0

y = 4 or y = -5

y = 4 is easy, then x = -2 or +2

y = -5 means x = i sqrt 5

now go back and see which of those solutions work in the original

if y = 4 and x = 2 then

yes, y = x^2

and

yes, 4 + 16 = 20

if y = 4 and x = -2 then

yes, y = x^2

yes, 4 + 16 = 20

if y = -5 and x = i sqrt 5

yes, y = x^2

yes, -5 + 25 = 20

- Math -
**Damon**, Tuesday, June 19, 2012 at 7:57pmI left out y = -5, x = -i sqrt 5

y = (-isqrt5)^2 = -5 yes

-5 + 25 = 20 yes

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