Post a New Question

chemistry

posted by on .

Nitrogen-13 has a half-life of 10 minutes. Given a starting mass of 2.00 g of nitrogen-13, how many grams will remain at the end of 30 minutes?

  • chemistry - ,

    k = 0.693/t1/2
    ln(No/N) = kt
    No = 2.00
    N = unknown
    k from above
    t = 30 min
    Solve for N.

    You can also use this.
    30 min is obviously 3 half lives; therefore, 23 = 8 and 2.00 x (1/8) = ?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question