Physics
posted by LaWanda on .
A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s2 until it stops. What distance does the train travel while slowing down?

v^2 = u^2  2*a*s
here, v = 0 (final speed)
u = 24 m/s
a = 0.065 m/s^2
Solve above to obtain s  distance covered while slowing down.