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Posted by on Tuesday, June 19, 2012 at 8:13am.

If 200 of the adults surveyed were in the age category of 24 and under and they provided a standard deviation of $14.50, construct a 95% confidence interval for the weekly average expenditure on fast food for adults 24 years of age and under. Assume fast food weekly expenditures are normally distributed.

  • Statistics - , Tuesday, June 19, 2012 at 10:29am

    95% = mean ± 1.96 SEm

    SEm = SD/√n

    Do you know the mean?

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