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April 16, 2014

April 16, 2014

Posted by **Helpme** on Tuesday, June 19, 2012 at 6:04am.

- Physics -
**drwls**, Tuesday, June 19, 2012 at 8:01amAdd the three displacement vectors.

2 i + (3 sin40 j + 3 cos40 i) + 2.5 j

= (2+3cos40) i + (2.5+3sin40) j

Magnitude of displacement

= sqrt[4.298^2 + 4.428^2]

= 6.171 cm

Direction = arctan 4.298/4.428

= 44.2 deg N of E

- Physics -
**Helpme**, Tuesday, June 19, 2012 at 8:59amThank You!!

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