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December 19, 2014

December 19, 2014

Posted by **Yun Gao** on Tuesday, June 19, 2012 at 12:39am.

a) determine the total cost at the level of production of 50 pizzas a day.

b) determine the production level that would minimize the average daily cost per pizza.

c) what is the minimum average daily cost per pizza?

- Calculus -
**Damon**, Tuesday, June 19, 2012 at 3:11amcost per pizza at x = 50 is

[.00025(50)^2 + 8(50) +10 ]/50 = 8.21

* 50 = 410.63

dc/dx = [x (.0005 x + 8) -.00025x^2-8x-10) ]/x^2

when is the numerator zero?

.0005 x^2 + 8 x -.00025 x^2 -8 x -10 = 0

.00025 x^2 = 10

x = 200

for c, use 200 for x

- Calculus -
**drwls**, Tuesday, June 19, 2012 at 3:16am(a) Plug in 50 for x and compute C(x).

(b) Solve for the value of x for which

C'(x) = dC(x)/dx = = 0.00025 x -20/x

= 0

25x^2 = 20,000

(c) Compute C(x) using the value of x from (b)

- Calculus -
**Yun Gao**, Tuesday, June 19, 2012 at 9:24pmthanks :)

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