Posted by **Henry** on Tuesday, June 19, 2012 at 12:26am.

differentiate each function

a) y = cos^3x

b) y = sin(x^3)

c) y = sin^2 xcos3x

my answers:

a) y' = 3cos^2 x(-sinx)

b) y' = cos(x^3)(3x^2)

c) for this one, i don't know which one is correct. i got 2 different answers but i think they may be the same.. im not sure, i did it twice and got 2 diff answers, please let me know which is right or if they are both wrong. first answer for c: y' = 2sinxcosxcos3x + 3cos2x(-sinx)sin^2x or 2nd answer for c: y' = 2sinxcosxcos3x + (-sin3x)(3)(sin^2x)

thank you

## Answer This Question

## Related Questions

- Trigonometry - Solve the equation for solutions in the interval 0<=theta<...
- TRIG! - Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...
- calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...
- calculus - Could someone check my reasoning? thanx Find the derivative of the ...
- Calculus - differentiate each function a) y = cos^3x b) y = sin(x^3) c) y = sin^...
- Calculus - Integrate 1/sinx dx using the identity sinx=2(sin(x/2)cos(x/2)). I ...
- Mathematics - Trigonometric Identities - Let y represent theta Prove: 1 + 1/tan^...
- Calc. - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln...
- Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...
- Mathematics - Trigonometric Identities - Prove: sin^2x - sin^4x = cos^2x - cos^...

More Related Questions